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-16x^2+2x+100=0
a = -16; b = 2; c = +100;
Δ = b2-4ac
Δ = 22-4·(-16)·100
Δ = 6404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6404}=\sqrt{4*1601}=\sqrt{4}*\sqrt{1601}=2\sqrt{1601}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1601}}{2*-16}=\frac{-2-2\sqrt{1601}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1601}}{2*-16}=\frac{-2+2\sqrt{1601}}{-32} $
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